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Given a mixed array of number and string representations of integers, add up the non-string integers and subtract this from the total of the string integers. Return as a number. Solution: def div_con(arr): x = sum(i for i in arr if isinstance(i, int)) y = sum(int(i) for i in arr if isinstance(i, str)) return x - y

Complete the function that takes two numbers as input, num and nth and return the nth digit of num (counting from right to left). Note If num is negative, ignore its sign and treat it as a positive value If nth is not positive, return -1 Keep in mind that 42 = 00042. This means that findDigit(42, 5) would return 0 Examples(num, nth --> output) 5673, 4 --> 5 129, 2 --> 2 -2825, 3 --> 8 -456, 4 --..

이토록 뜻밖의 뇌과학 뇌과학에 대해 쉽게 그리고 핵심을 잘 설명해 준 책이다. 특히 우리의 뇌는 완성되어 태어나는 것이 아니라 양육을 통해 만들어진다는 점이 가장 인상적이었다. 그래서 양육이 중요한 것이구나! 성인이 되어도 뇌는 일생동안 변할 수 있는데 이를 '뇌가소성'이라고 한다. 단어는 익히 들었지만 그 원리에 대해서는 잘 몰랐는데 이 책을 통해 자세히 알게 되었다. 뇌는 외부세계와의 상호작용을 통해 '세부조정'과 '가지치기'가 일어나는데 이때 뇌가 변하게 된다! 이에 대해 더 자세한 내용은 책에서 볼 수 있다. 나는 이 '세부조정'과 '가지치기'를 적극 활용하면 성인도 스스로를 양육할 수 있겠다는 생각이 들었다. 예를 들어 무언가를 해야 할 때 두렵거나 불안한 마음이 든다면 그것은 뇌가 과거의 경험..

Write a function to get the first element(s) of a sequence. Passing a parameter n (default=1) will return the first n element(s) of the sequence. If n == 0 return an empty sequence [] Examples arr = ['a', 'b', 'c', 'd', 'e'] first(arr) # --> ['a'] first(arr, 2) # --> ['a', 'b'] first(arr, 3) # --> ['a', 'b', 'c'] first(arr, 0) # --> [] Solution: def first(seq: list[str], n:int = 1) -> list[str]:..

Filter the number Oh, no! The number has been mixed up with the text. Your goal is to retrieve the number from the text, can you return the number back to its original state? Task Your task is to return a number from a string. Details You will be given a string of numbers and letters mixed up, you have to return all the numbers in that string in the order they occur. Solution: def filter_string(..

Write function parse_float which takes a string/list and returns a number or 'none' if conversion is not possible. Solution: def parse_float(string: str) -> float | None: try: return float(string) except (ValueError, TypeError): return None

Your classmates asked you to copy some paperwork for them. You know that there are 'n' classmates and the paperwork has 'm' pages. Your task is to calculate how many blank pages do you need. If n < 0 or m < 0 return 0. Example: n= 5, m=5: 25 n=-5, m=5: 0 Waiting for translations and Feedback! Thanks! Solution: def only_int(func): def wrapper(n, m): if n < 0 or m < 0: return 0 return func(n, m) r..

For this problem you must create a program that says who ate the last cookie. If the input is a string then "Zach" ate the cookie. If the input is a float or an int then "Monica" ate the cookie. If the input is anything else "the dog" ate the cookie. The way to return the statement is: "Who ate the last cookie? It was (name)!" Ex: Input = "hi" --> Output = "Who ate the last cookie? It was Zach! ..

You will be given an array a and a value x. All you need to do is check whether the provided array contains the value. Array can contain numbers or strings. X can be either. Return true if the array contains the value, false if not. Solution: check: bool = lambda x, y : y in x

Create a function that gives a personalized greeting. This function takes two parameters: name and owner. Use conditionals to return the proper message: case name equals owner : 'Hello boss' otherwise : 'Hello guest' Solution: def greet(name: str, owner: str) -> str: return f"Hello {name == owner and 'boss' or 'guest'}"