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Write a function reverse which reverses a list (or in clojure's case, any list-like data structure) (the dedicated builtin(s) functionalities are deactivated) Solution: def reverse(lst): result = list() for _ in range(len(lst)): result.append(lst.pop()) return result

Consider the word "abode". We can see that the letter a is in position 1 and b is in position 2. In the alphabet, a and b are also in positions 1 and 2. Notice also that d and e in abode occupy the positions they would occupy in the alphabet, which are positions 4 and 5. Given an array of words, return an array of the number of letters that occupy their positions in the alphabet for each word. F..

You and a friend have decided to play a game to drill your statistical intuitions. The game works like this: You have a bunch of red and blue marbles. To start the game you grab a handful of marbles of each color and put them into the bag, keeping track of how many of each color go in. You take turns reaching into the bag, guessing a color, and then pulling one marble out. You get a point if you..

Count the number of occurrences of each character and return it as a (list of tuples) in order of appearance. For empty output return (an empty list). Consult the solution set-up for the exact data structure implementation depending on your language. Example: ordered_count("abracadabra") == [('a', 5), ('b', 2), ('r', 2), ('c', 1), ('d', 1)] Solution: def ordered_count(inp): from collections impo..

Write a function get_char() / getChar() which takes a number and returns the corresponding ASCII char for that value. Example: get_char(65) should return: 'A' Solution: get_char = lambda x: chr(x)

Ahoy matey! You are a leader of a small pirate crew. And you have a plan. With the help of OOP you wish to make a pretty efficient system to identify ships with heavy booty on board! Unfortunately for you, people weigh a lot these days, so how do you know if a ship is full of gold and not people? You begin with writing a generic Ship class / struct: class Ship: def __init__(self, draft, crew): s..

글똥이 개발 슬랙 봇 '글똥이'를 개발하고 있다. 글똥이는 글 제출과 패스에 대한 데이터를 수집하여 스프레드시트에 적재하는 봇이다. 이번주에는 집에 와서 밤늦게까지 글똥이만 붙잡았다. 직전까지는 기능만 구현한 상태였으나 이를 클라우드 환경에서 FastAPI 프레임워크로 감싸는 과정이 꽤나 오래 걸렸다. 이 과정에서 백엔드 서버를 무료로 배포하는 방법이나 FastAPI 에서 Slack_bolt를 사용하는 방법 등을 배울 수 있었다! 개발 과정이 너무 재밌어서 운동이나 다른 것들을 잊어버릴 정도였다.. 오는 주에는 후딱 마무리 짓고 실전 테스트를 해보자. 방탈출 & 크라임씬 회사 동료들과 수요일, 토요일에 각각 방탈출, 크라임씬을 다녀왔다. 나는 추리하고 연기하는 게임을 좋아한다. 그래서 방탈출이나 크라임씬..

You can print your name on a billboard ad. Find out how much it will cost you. Each character has a default price of £30, but that can be different if you are given 2 parameters instead of 1. You can not use multiplier "*" operator. If your name would be Jeong-Ho Aristotelis, ad would cost £600. 20 leters * 30 = 600 (Space counts as a character). Solution: def billboard(name, price=30): return s..

Time to test your basic knowledge in functions! Return the odds from a list: [1, 2, 3, 4, 5] --> [1, 3, 5] [2, 4, 6] --> [] Solution: odds = lambda x: [i for i in x if i & 1]

I will give you an integer. Give me back a shape that is as long and wide as the integer. The integer will be a whole number between 1 and 50. Example n = 3, so I expect a 3x3 square back just like below as a string: +++ +++ +++ Solution: def generate_shape(n: int) -> str: return "\n".join("+" * n for i in range(n))