0120. Alphabet symmetry

Consider the word "abode". We can see that the letter a is in position 1 and b is in position 2. In the alphabet, a and b are also in positions 1 and 2. Notice also that d and e in abode occupy the positions they would occupy in the alphabet, which are positions 4 and 5.

Given an array of words, return an array of the number of letters that occupy their positions in the alphabet for each word. For example,

solve(["abode","ABc","xyzD"]) = [4, 3, 1]

See test cases for more examples.

Input will consist of alphabet characters, both uppercase and lowercase. No spaces.

Good luck!

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Solution:

def solve(arr):
    alphabet = "abcdefghijklmnopqrstuvwxyz"
    return [sum(int(a == b) for a, b in zip(i.lower(), alphabet)) for i in arr]