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Given a non-empty array of integers, return the result of multiplying the values together in order. Example: [1, 2, 3, 4] => 1 * 2 * 3 * 4 = 24 Solution: def grow(arr, i=1): return grow(arr, i*arr.pop()) if arr else i

Mr. Scrooge has a sum of money 'P' that he wants to invest. Before he does, he wants to know how many years 'Y' this sum 'P' has to be kept in the bank in order for it to amount to a desired sum of money 'D'. The sum is kept for 'Y' years in the bank where interest 'I' is paid yearly. After paying taxes 'T' for the year the new sum is re-invested. Note to Tax: not the invested principal is taxed..

Description: Write a function, persistence, that takes in a positive parameter num and returns its multiplicative persistence, which is the number of times you must multiply the digits in num until you reach a single digit. For example (Input --> Output): 39 --> 3 (because 3*9 = 27, 2*7 = 14, 1*4 = 4 and 4 has only one digit) 999 --> 4 (because 9*9*9 = 729, 7*2*9 = 126, 1*2*6 = 12, and finally 1..

Summation Write a program that finds the summation of every number from 1 to num. The number will always be a positive integer greater than 0. For example: summation(2) -> 3 1 + 2 summation(8) -> 36 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 Solution 1. Repeat the number incrementing by 1 as much as 'num'. 2. Add up all the calculated numbers and return them. JS code :: // js :: for var summation = function ..