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The Feast of Many Beasts All of the animals are having a feast! Each animal is bringing one dish. There is just one rule: the dish must start and end with the same letters as the animal's name. For example, the great blue heron is bringing garlic naan and the chickadee is bringing chocolate cake. Write a function feast that takes the animal's name and dish as arguments and returns true or false ..

Write a function reverse which reverses a list (or in clojure's case, any list-like data structure) (the dedicated builtin(s) functionalities are deactivated) Solution: def reverse(lst): result = list() for _ in range(len(lst)): result.append(lst.pop()) return result

Consider the word "abode". We can see that the letter a is in position 1 and b is in position 2. In the alphabet, a and b are also in positions 1 and 2. Notice also that d and e in abode occupy the positions they would occupy in the alphabet, which are positions 4 and 5. Given an array of words, return an array of the number of letters that occupy their positions in the alphabet for each word. F..

You and a friend have decided to play a game to drill your statistical intuitions. The game works like this: You have a bunch of red and blue marbles. To start the game you grab a handful of marbles of each color and put them into the bag, keeping track of how many of each color go in. You take turns reaching into the bag, guessing a color, and then pulling one marble out. You get a point if you..

Count the number of occurrences of each character and return it as a (list of tuples) in order of appearance. For empty output return (an empty list). Consult the solution set-up for the exact data structure implementation depending on your language. Example: ordered_count("abracadabra") == [('a', 5), ('b', 2), ('r', 2), ('c', 1), ('d', 1)] Solution: def ordered_count(inp): from collections impo..

Write a function get_char() / getChar() which takes a number and returns the corresponding ASCII char for that value. Example: get_char(65) should return: 'A' Solution: get_char = lambda x: chr(x)

Ahoy matey! You are a leader of a small pirate crew. And you have a plan. With the help of OOP you wish to make a pretty efficient system to identify ships with heavy booty on board! Unfortunately for you, people weigh a lot these days, so how do you know if a ship is full of gold and not people? You begin with writing a generic Ship class / struct: class Ship: def __init__(self, draft, crew): s..

You can print your name on a billboard ad. Find out how much it will cost you. Each character has a default price of £30, but that can be different if you are given 2 parameters instead of 1. You can not use multiplier "*" operator. If your name would be Jeong-Ho Aristotelis, ad would cost £600. 20 leters * 30 = 600 (Space counts as a character). Solution: def billboard(name, price=30): return s..

Time to test your basic knowledge in functions! Return the odds from a list: [1, 2, 3, 4, 5] --> [1, 3, 5] [2, 4, 6] --> [] Solution: odds = lambda x: [i for i in x if i & 1]

I will give you an integer. Give me back a shape that is as long and wide as the integer. The integer will be a whole number between 1 and 50. Example n = 3, so I expect a 3x3 square back just like below as a string: +++ +++ +++ Solution: def generate_shape(n: int) -> str: return "\n".join("+" * n for i in range(n))