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Count the number of occurrences of each character and return it as a (list of tuples) in order of appearance. For empty output return (an empty list).
Consult the solution set-up for the exact data structure implementation depending on your language.
Example:
ordered_count("abracadabra") == [('a', 5), ('b', 2), ('r', 2), ('c', 1), ('d', 1)]
Solution:
def ordered_count(inp):
from collections import Counter
count_dict = Counter(list(inp))
return [tuple for tuple in zip(count_dict.keys(), count_dict.values())]
from collections import Counter
def ordered_count(inp):
return list(Counter(inp).items())
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