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1204. Odd or Even? 본문

나는 이렇게 학습한다/Algorithm & SQL

1204. Odd or Even?

daco2020 2022. 12. 4. 21:36

Task:

Given a list of integers, determine whether the sum of its elements is odd or even.

Give your answer as a string matching "odd" or "even".

If the input array is empty consider it as: [0] (array with a zero).

Examples:

Input: [0]
Output: "even"

Input: [0, 1, 4]
Output: "odd"

Input: [0, -1, -5]
Output: "even"



Solution:

String oddOrEven(List<int> array) {
  int result = _sum_array(array);
  return result % 2 == 0 ? "even" : "odd";
}

int _sum_array(List<int> array) {
  int result = 0;
  for (int i in array) {
    result += i;
  }
  return result;
}
String oddOrEven(List<int> array) =>array.reduce((a, b) => a + b).isEven ? 'even' : 'odd';
import 'package:collection/collection.dart';

String oddOrEven(List<int> array) {
  return array.sum.isEven ? "even" : "odd";
}


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