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Create a function with two arguments that will return an array of the first n multiples of x.
Assume both the given number and the number of times to count will be positive numbers greater than 0.
Return the results as an array or list ( depending on language ).
Examples
countBy(1,10) === [1,2,3,4,5,6,7,8,9,10]
countBy(2,5) === [2,4,6,8,10]
Solution:
List<int> countBy(int x, int n) {
List<int> results = [];
for (int i=1; i<=n; i++) {
results.add(i*x);
}
return results;
}
List<int> countBy(int c, int x) => List.generate(x, (i) => (i + 1) * c);
List<int> countBy(int x, int n) {
return [for(var i = 1; i<=n; i++) x*i];
}
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