0824. N-th Power

This kata is from check py.checkio.org

You are given an array with positive numbers and a non-negative number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.

Let's look at a few examples:

• array = [1, 2, 3, 4] and N = 2, then the result is 3^2 == 9;
• array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.

Solution:

def index(array, n):     return array[n]**n if len(array) > n else -1