Count the number of occurrences of each character and return it as a (list of tuples) in order of appearance. For empty output return (an empty list). Consult the solution set-up for the exact data structure implementation depending on your language. Example: ordered_count("abracadabra") == [('a', 5), ('b', 2), ('r', 2), ('c', 1), ('d', 1)] Solution: def ordered_count(inp): from collections impo..