나는 이렇게 학습한다/Algorithm & SQL

1023. No Loops 2 - You only need one

daco2020 2022. 10. 23. 21:00
반응형

No Loops Allowed

You will be given an array a and a value x. All you need to do is check whether the provided array contains the value, without using a loop.

Array can contain numbers or strings. x can be either. Return true if the array contains the value, false if not. With strings you will need to account for case.

Looking for more, loop-restrained fun? Check out the other kata in the series:



Solution:

def check(arr, x): 
    import collections
    return bool(collections.Counter(arr).get(x))


반응형

'나는 이렇게 학습한다 > Algorithm & SQL' 카테고리의 다른 글

1025. Exclusive "or" (xor) Logical Operator  (0) 2022.10.26
1024. Sum The Strings  (0) 2022.10.24
1022. Area of a Square  (0) 2022.10.22
1021. USD => CNY  (0) 2022.10.21
1020. Convert a string to an array  (0) 2022.10.20