Row Weights

Scenario

Several people are standing in a row divided into two teams.
The first person goes into team 1, the second goes into team 2, the third goes into team 1, and so on.

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Task

Given an array of positive integers (the weights of the people), return a new array/tuple of two integers, where the first one is the total weight of team 1, and the second one is the total weight of team 2.

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Notes

• Array size is at least 1.
• All numbers will be positive.

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  Input >> Output Examples

rowWeights([13, 27, 49])  ==>  return (62, 27)

Explanation:

The first element 62 is the total weight of team 1, and the second element 27 is the total weight of team 2.

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rowWeights([50, 60, 70, 80])  ==>  return (120, 140)

Explanation:

The first element 120 is the total weight of team 1, and the second element 140 is the total weight of team 2.

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rowWeights([80])  ==>  return (80, 0)

Explanation:

The first element 80 is the total weight of team 1, and the second element 0 is the total weight of team 2.

 

 

Solution:

def row_weights(array):
    team1 = sum([i for i in array[::2]])
    return (team1, sum(array)-team1)

 

Other Solution:

def row_weights(array):
    return sum(array[::2]), sum(array[1::2])

def row_weights(array):
    odd = 0
    even = 0
    for i in range(len(array)):
        if i%2 == 0:
            odd += array[i]
        else:
            even += array[i]
    return odd, even

row_weights = lambda arr: (sum(arr[::2]), sum(arr[1::2]))