Replace With Alphabet Position

Welcome.

In this kata you are required to, given a string, replace every letter with its position in the alphabet.

If anything in the text isn't a letter, ignore it and don't return it.

"a" = 1, "b" = 2, etc.

Example

alphabet_position("The sunset sets at twelve o' clock.")

Should return "20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11" ( as a string )

 

 

Solution:

from typing import List


def alphabet_position(text: str) -> str:
    alphabete = _check_alphabet(text)
    positions = _get_alphabet_positions(alphabete)
    alphabet_position = ' '.join(positions)
    return alphabet_position

def _check_alphabet(text: str) -> List[str]:
    return [i for i in text if i.isalpha()]

def _get_alphabet_positions(alphabete: List[str]) -> List[str]:
    start_position = ord("a") - 1
    return [str((ord(alphabet.lower())-start_position)) for alphabet in alphabete]

1. Check whether the text is alphabetic.
2. Convert Alphabet to Position Number
3. Return the converted alphabetic position number.

 

 

Best Practice:

def alphabet_position(text):
    return ' '.join(str(ord(c) - ord("a")+1) for c in text.lower() if c.isalpha())