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SQL Basics - Monsters using CASE 본문

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SQL Basics - Monsters using CASE

daco2020 2022. 7. 12. 20:54

You have access to two tables named top_half and bottom_half, as follows:

top_half schema

  • id
  • heads
  • arms

bottom_half schema

  • id
  • legs
  • tails

You must return a table with the format as follows:

output schema

  • id
  • heads
  • legs
  • arms
  • tails
  • species

The IDs on the tables match to make a full monster. For heads, arms, legs and tails you need to draw in the data from each table.

For the species, if the monster has more heads than arms, more tails than legs, or both, it is a 'BEAST' else it is a 'WEIRDO'. This needs to be captured in the species column.

All rows should be returned (10).

Tests require the use of CASE. Order by species.

 

Solution:

SELECT 
  *,
  CASE WHEN heads > arms THEN 'BEAST'
  WHEN tails > legs THEN 'BEAST'
  ELSE 'WEIRDO'
  END AS species
FROM 
  top_half t 
JOIN 
  bottom_half b ON t.id = b.id
ORDER BY species

 

Result:

id heads arms legs tails species
10 6349 395 27936 6096 BEAST
1 367 88502 228 558 BEAST
3 199 314 1688 46602 BEAST
4 896 998 109 867 BEAST
5 998 4106 665 50349 BEAST
6 238 1867 4183 32453 BEAST
7 8330 733 8116 517 BEAST
8 9387 586 33200 79905 BEAST
9 95384 6440 82463 7845 BEAST
2 180 9824 5506 291 WEIRDO