나는 이렇게 학습한다/Algorithm & SQL

SQL: Padding Encryption

daco2020 2022. 6. 23. 22:34
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You are given a table with the following format:

** encryption table schema **

  • md5
  • sha1
  • sha256

Problem is the table looks so unbalanced - the sha256 column contains much longer strings. You need to balance things up. Add '1' to the end of the md5 addresses as many times as you need to to make them the same length as those in the sha256 column. Add '0' to the beginning of the sha1 values to achieve the same result.

Return as:

** output table schema **

  • md5
  • sha1
  • sha256

 

Solution:

SELECT 
  RPAD(md5, LENGTH(sha256),'1') AS md5,
  LPAD(sha1, LENGTH(sha256), '0') AS sha1,
  sha256 
FROM 
  encryption

  

Result:

md5 sha1 sha256
2fb8ef75c96f669bfc7409eb09b0987f11111111111111111111111111111111 000000000000000000000000ab7a651e7f20b66e84fefc785941727250eb6c37 30f7a59bfe25d47a0edbb330c556502c5aa6ca771d8a65776c12f3beee80f4b9
f3d2d7bec379fbd23eb4658d35b93f7211111111111111111111111111111111 000000000000000000000000ccd512990187d8a212a43ec06af712935bf7cd84 ee9729a138b001a9f0d1d623db58ef8b39df89df0609c07821fb1b70106bca90
5ceb0e13d80eb7343e5bb66f4121790a11111111111111111111111111111111 0000000000000000000000007519474b1954c2e4e04d6a3afc63ec05c8070f44 26e06160bbf5e0057d9b252a62bd5e3d7fb2c8325c5a8965246b8e10daa90fc3
1ecd061670f0fc89ef627a57826a05fa11111111111111111111111111111111 00000000000000000000000020bf3c9d5c5394beb34d85cb0ce61267e29fe5cf 87cad197a6b50c0ab068162c5472313b2b24f9f1ad81b03ad5f9c571dcd20d7b

 

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