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For this challenge you need to create a simple GROUP BY statement, you want to group all the people by their age and count the people who have the same age.
people table schema
- id
- name
- age
select table schema
- age [group by]
- people_count (people count)
Solution:
SELECT
age,
COUNT(age) AS people_count
FROM
people
GROUP BY
age
Result:
age | people_count |
8 | 10 |
4 | 7 |
1 | 16 |
5 | 8 |
3 | 7 |
0 | 9 |
9 | 13 |
6 | 12 |
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