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Description:
Given two integers a and b, which can be positive or negative, find the sum of all the integers between and including them and return it. If the two numbers are equal return a or b.
Note: a and b are not ordered!
Examples (a, b) --> output (explanation)
(1, 0) --> 1 (1 + 0 = 1)
(1, 2) --> 3 (1 + 2 = 3)
(0, 1) --> 1 (0 + 1 = 1)
(1, 1) --> 1 (1 since both are same)
(-1, 0) --> -1 (-1 + 0 = -1)
(-1, 2) --> 2 (-1 + 0 + 1 + 2 = 2)
Solution:
1. Sort the low and high numbers.
2. Returns the sum of all numbers between two numbers.
JS code ::
function getSum(a, b){
// Sort ascending
let arr = [a, b].sort(function(a, b){return a - b})
let answer = 0
// Find the range
for (let i = arr[0]; i < arr[1]+1; i++){
answer += i
}
return answer
}
Python code ::
def get_sum(a,b):
a, b = min(a,b), max(a,b)
return sum([ i for i in range(a,b+1)])
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